Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } 2. A particle moves according to the equation x = 10t^2, where x is in meters and t is in seconds. (a) Find the average velocity for the time interval from 2.00 s to 3.00 s. (b) Find the average velocity for the time interval from 2.00 s to 2.10 s. Hint overline(v) = (∆x)/(∆t) Answer (a) 50.0 m//s (b) 41.0 m//s Show Steps Given: x = 10t^2 or (a) x_((2)) = 10times(2.00)^2 = 40.0 m x_((3)) = 10times(3.00)^2 = 90.0 m overline(v) = (90 m - 40 m)/(3.00s - 2.00s) = color(red)(50.0 m//s) (b) x_((2)) = 10times(2.00)^2 = 40.0 m x_((2.1)) = 10times(2.10)^2 = 44.1 m overline(v) = (44.1 m - 40 m)/(2.10s - 2.00s) = color(red)(41.0.0 m//s)