2. Show that the rms speed of molecules in a gas is given by `v_(rms) = sqrt(3P//ρ)`, where `P` is the pressure in the gas, and `ρ` is the gas density.
2. Show that the rms speed of molecules in a gas is given by v_(rms) = sqrt(3P//ρ), where P is the pressure in the gas, and ρ is the gas density.
Hint
`PV = NkT` `v_(rms) =sqrt((3kT)/m)` `ρ = M/v`
Answer
Show Steps
Equations: `PV = NkT` `v_(rms) =sqrt((3kT)/m)` `ρ = m/V` Solution: Total mass `M = Nm` `ρ = M/V => V = M/ρ =(Nm)/ρ` `PV = NkT => T = (PV)/(Nk) = (P((Nm)/ρ))/(Nk) = (Pm)/(ρk)` `v_(rms) =sqrt((3kT)/m)` `v_(rms) =sqrt((3k((Pm)/(ρk)))/m)` `v_(rms) =sqrt((3P)/ρ)`