7. A car drove into the highway. The driver accelerates the car from `8.0\ m//s` to `25.0\ m//s` in 10.0 seconds. What is the acceleration of the car?
7. A car drove into the highway. The driver accelerates the car from 8.0\ m//s to 25.0\ m//s in 10.0 seconds. What is the acceleration of the car? `a= (∆v)/(∆t) `
`∆v = v_f - v_i`
`a=1.70\ m//s^2`
Given:
`v_i = 8.0\ m//s`
`v_f = 25.0\ m//s`
`∆t = 10.0\ s`
Equation:
`a= (∆v)/(∆t) `
`∆v = v_f - v_i`
Solution:
`a= (v_f - v_i)/(∆t) `
`a= ((25.0\ m//s) -(8.0\ m//s))/(10.0\ s) `
`a=1.70\ m//s^2` |