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9. A car was initially at rest and started with an acceleration of `3.0 m //s^2`. How far did it traveled after 10.0 seconds?
9. A car was initially at rest and started with an acceleration of 3.0 m //s^2. How far did it traveled after 10.0 seconds? `∆x = v_it + 1/2 a t^2`
`∆x = 150\ m`
Given:
`v_i = 0`
`a = 3.0\ m//s^2`
`∆t = 10.0 s`
Equation:
`∆x = v_it + 1/2 a t^2`
Solution:
`∆x = v_it + 1/2 a t^2`
`∆x = 0 + 1/2 (3.0\ m//s^2) (10.0\ s)^2`
`∆x = 150\ m` |