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2. How much work is required to stop a `1000\ kg` car traveling at `10\ m//s`
2. How much work is required to stop a 1000\ kg car traveling at 10\ m//s `KE = 1/2mv^2`
`W = ∆KE`
`W = - 5.0 times 10^4 J`
Given:
`m = 1000kg`
`v_i = 10\ m//s`
`v_f =0`
solution:
`W = ∆KE = KE_f -KE_i` and `KE = 1/2mv^2`
`W = 1/2m(v_f)^2 - 1/2m(v_i)^2`
`W = 0-1/2(1000\ kg)((10\ m//s))^2`
`W = - 5.0times 10^4\ J` |