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4. An electric clothes dryer has a heating element with a resistance of `9.6\ Ω`.
(a) What is the current in the element when it is connected to `240\ V`?
(b) How much charge passes through the element in `50` min?
4. An electric clothes dryer has a heating element with a resistance of 9.6\ Ω.
(a) What is the current in the element when it is connected to 240\ V?
(b) How much charge passes through the element in 50 min? `V = IR`
`I = (∆Q)/(∆t)`
(a)
`I = 25\ A`
(b)
`∆Q=7.5 × 10^4/ C`
Given:
`R = 9.6\ Ω`
`V = 240\ V`
`∆t = 50 min = 50 × 60\ s`
Equations
`V = IR`
`I = (∆Q)/(∆t)`
Solution:
(a)
`V = IR`
`=>`
`I = V/R`
`I = (240\ V)/(9.6\ Ω)`
`I = 25\ A`
(b)
`I = (∆Q)/(∆t)`
`=>`
`∆Q=I∆t`
`∆Q=(25\ A)(50 × 60\ s)`
`∆Q=7.5 × 10^4\ C` |