3. Solve `x` `x^2 -2x-3=0`
3. Solve x x^2 -2x-3=0
Hint
`x = (-b ± sqrt(b^2-4ac))/(2a)`
Answer
`x =4 or x=-1`
Show Steps
Use quadratic formula: `x = (-b ± sqrt(b^2-4ac))/(2a)` where `a = 1` `b =-2 ` `c =-3` substitute `a\ b` and `c` to the quadratic formula, we get `x = (-(-2) ± sqrt((-2)^2-4(1)(-3)))/(2(1))` `x = (2 ± 4)/(2)` `x =4 or x=-1`