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6. Car `A` is `500\ m` ahead of car `B`. Both cars are driving toward North. Car `A` travels with a speed of `3.0 \m//s` and car `B` travels with a speed of `5.0\ m//s`. How long will it take for car B to catch up with car A?
6. Car A is 500\ m ahead of car B. Both cars are driving toward North. Car A travels with a speed of 3.0 \m//s and car B travels with a speed of 5.0\ m//s. How long will it take for car B to catch up with car A? `x_f = x_i + v∆t`
`∆t = 250/ s`
Given:
`x_(A_i) = 500\ m`
`x_(B_i) = 0`
`v_A = 3.0\ m//s`
`v_B = 5.0\ m//s`
Equation:
`x_f = x_i + v∆t`
Solution:
At the moment car B catch up with car A, both cars at the same position, `x_(A_f) = x_(B_f)`.
`(500\ m) + (3.0\ m//s)∆t = 0 + ( 5.0\ m//s) ∆t`
`∆t =(500\ m)/(( 5.0\ m//s)-(3.0\ m//s))`
`∆t = 250/ s` |