4. Solve `t` `2 + 20t +1/2(-9.8)t^2 =5`


Hint
`t = (-b ± sqrt(b^2-4ac))/(2a)`
Answer
`=> t_1 = 0.16, t_2 = 3.9`
Show Steps
1) Simplify equation: `=> -3 + 20t -4.9t^2 =0` 2) Use quadratic formula: `t = (-b ± sqrt(b^2-4ac))/(2a)` where `a = -4.9` `b =20 ` `c =-3` `=> t = (-20 ± sqrt((-20)^2-4(-4.9)(-3)))/(2(-4.9))` `=> t = (-20±18.47)/-9.8` `=> t_1 = 0.16, t_2 = 3.9`