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1. How does the number of atoms in a 26.5-gram gold ring compare to the number in a silver ring or the same mass?
(Atomic mass of gold : `197\ u`; Atomic mass of silver: `108\ u`)
1. How does the number of atoms in a 26.5-gram gold ring compare to the number in a silver ring or the same mass?
(Atomic mass of gold : 197\ u; Atomic mass of silver: 108\ u) Given:
`m = 26.5\ g`
`AM_(Au) = 197\ u`
`AM_(Ag) = 108\ u`
Known: `1\ u = 1.66times10^(-27) kg//at om`
Solution:
Number of gold (`N_(Au)`) compare with number of silver (`N_(Ag)`)
`N_(Au)/N_(Ag) = (m/(AM_(Au) 1.66times10^(-27) kg//at om))/ (m/(AM_(Ag) 1.66times10^(-27) kg//at om)) `
`N_(Au)/N_(Ag) =(AM_(Ag))/(AM_(Au)) = (108\ u)/(197\ u)`
`N_(Au)/N_(Ag) = 0.548`
`N_(Au)= 0.548 N_(Ag) ` |