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2. A storage tank at STP contains `18.5\ kg` of nitrogen(`N_2`).
(a) What is the volume of the tank?
(b) What is the pressure if an additional `15.0\ kg` of nitrogen is added without changing the temperature?
2. A storage tank at STP contains 18.5\ kg of nitrogen(N_2).
(a) What is the volume of the tank?
(b) What is the pressure if an additional 15.0\ kg of nitrogen is added without changing the temperature? `PV = nRT`
at STP 1 mol gas is `22.4 times 10^(-3) m^3`
`T(K) = 273\ K`
`P = 101\ kPa`
(a)
`V = 14.8 m^3`
(b)
`P_2 = 183\ kPa`
Given:
at STP 1 mol gas is `22.4 times 10^(-3) m^3`
`T(K) = 273\ K`
`P = 101\ kPa`
`m_(N_2) = 18.5\ kg`
`am_(N_2) = 28.0\ u = 28.0times10^(-3) g/mol`
Equation:
`PV = nRT`
Solution:
(a)
`n = (18.5\ kg)/(28.0times10^(-3) g/mol) = 660.71\ mol`
`V = (660.71\ mol)(22.4 times 10^(-3) m^3//mol)`
`V = 14.8 m^3`
(b)
`n = (18.5\ kg + 15.0\ kg)/(28.0times10^(-3) g/mol) = 1196\ mol`
Since `T` and `V` not change.
`P_1/n_1 = (RT)/V = P_2/n_2`
`P_2 = P_1n_2/n_1`
`P_2 = 101\ kPa (1196\ mol)/(660.71\ mol)`
`P_2 = 183\ kPa` |