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Solving with Absolute Value 2
Often the absolute value will have more than just a variable in it. In this case we will have to solve the resulting equations when we consider the positive and negative possibilities. This is shown in the next example.
Example
`|2x − 1| = 7`
`|2x − 1| = 7` | Absolute value can be positive or negative |
`2x−1=7 or 2x−1=−7` | Two equations to solve |
Now notice we have two equations to solve, each equation will give us a different solution. Both equations solve like any other two-step equation.
`2x−1=7` | `2x−1=-7` |
`2x−1color(red)(+1)=7color(red)(+1)` | `2x−1color(red)(+1)=-7color(red)(+1)` |
`2x=8` | `2x=-6` |
`(2x)/color(red)(2)=8/color(red)(2) ` | `(2x)/color(red)(2)=(-6)/color(red)(2) ` |
`x=4 ` | `x= -3` |
Example
`2−4|2x+3|=−18`
`2−4|2x+3|=−18 ` | Notice absolute value is not alone |
`2color(red)(-2)−4|2x+3|=−18color(red)(-2) ` | Subtract `2` from both sides |
`−4|2x+3|=−20` | Absolute value still not alone |
`(−4|2x+3|)/color(red)(-4)=(−20)/color(red)(-4)` | Divide both sides by `−4` |
`|2x+3|=5` | Absolute value can be positive or negative |
`2x+3=5` or `2x+3=−5` | Two equations to solve |
`2x+3=5` | `2x+3=−5` |
`2x+3color(red)(-3)=5color(red)(-3)` | `2x+3color(red)(-3)=-5color(red)(-3)` |
`2x=2` | `2x=-8` |
`(2x)/color(red)(2)=2/color(red)(2)` | `(2x)/color(red)(2)=(-8)/color(red)(2)` |
`x=1` | `x=−4` |
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