Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } 3. A 50.0 g Super Ball traveling at 25.0 m//s bounces off a brick wall and rebounds at 22.0 m//s. A high-speed camera records this event. If the ball is in contact with the wall for 3.50 ms, what is the magnitude of the average acceleration of the ball during this time interval? Hint a = (∆v)/(∆t) Answer -1.34 times 10^4 m//s^2 Show Steps Givens: v_i = 25.0 m//s v_f = -22.0 m//s ∆t = 3.50 ms Calculations: a = (∆v)/(∆t) = (v_f - v_i)/(∆t) a = (-22.0 m//s - 25.0 m//s)/(3.50 times 10^(-3)s) =color(red)(-1.34 times 10^4 m//s^2)