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3. How much tension must a rope withstand if it is used to accelerate a `100`-`kg` box vertically upward at `0.50\ m//s^2`. (use `g=-10\ m//s^2`)
3. How much tension must a rope withstand if it is used to accelerate a 100-kg box vertically upward at 0.50\ m//s^2. (use g=-10\ m//s^2) `sum F = ma`
`T = 1.1 times 10^3\ N`
Given:
`m = 100\ kg`
`a = 0.50\ m/s^2`
`g = -10\ m/s^2`
Equation
`sum F = ma`
Solution:
`T+mg = ma`
`T = ma-mg = m(a-g)`
`T = (100\ kg)((0.50\ m//s^2)-(-10\ m//s^2))`
`T = 1050\ N ≈ 1.1 times 10^3\ N` |