4. A 25.0-kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motion, after which a horizontal force of 60.0 N is required to keep the block moving with constant speed. Find (a) the coefficient of static friction and (b) the coefficient of kinetic friction between the block and the surface.
4. A 25.0-kg block is initially at rest on a horizontal surface. A horizontal force of 75.0 N is required to set the block in motion, after which a horizontal force of 60.0 N is required to keep the block moving with constant speed. Find (a) the coefficient of static friction and (b) the coefficient of kinetic friction between the block and the surface.
Hint
`f_k = µ_kn` `f_s = µ_sn`
Answer
(a) 0.306 (b) 0.245
Show Steps
Given: `f_s = 75.0 N` `f_k = 60 N` `m = 25.0\ kg` Equations: `f_k = µ_kn` `f_s = µ_sn` (a) `f_s = µ_s times n` `mu_s = f_s / n` `n = mg` `mu_s = f_s/(mg) = 75.0 / (25.0 times 9.8) = 0.306` (a) `f_k = mu_k times n` `mu_s = f_k / n` `n = mg` `mu_s = f_k/(mg) = 60.0 / (25.0 times 9.8) = 0.245`