3. A block weight `900\ N` was pulled up on an inclined plane with a force of `400\ N` shown below. Assume the inclined plane is frictionless.
a) What is IMA of this machine?
b) Calculate the theoretical `F_(i n)`.
c) What is AMA of this machine?
d) What is Mechanical efficiency of this machine?
3. A block weight 900\ N was pulled up on an inclined plane with a force of 400\ N shown below. Assume the inclined plane is frictionless.
a) What is IMA of this machine?
b) Calculate the theoretical F_(i n).
c) What is AMA of this machine?
d) What is Mechanical efficiency of this machine? `IMA = F_(out)/F_(i n)=L/H`
Efficiency`= (AMA)/(IMA)`
a)
`IMA =3.0`
b)
`F_(i n)= 300\ N`
c)
`AMA = 2.25`
d)
Efficiency`=0.75`
Given:
`F_(out) = 900\ N`
Actual `F_(i n) = 400\ N`
`L = 9.0\ m`
`H = 3.0\ m`
Equations:
`IMA = F_(out)/F_(i n)=L/H`
Efficiency`= (AMA)/(IMA)`
Solution:
a)
`IMA =L/H = (9.0\ m)/(3.0\ m)`
`IMA =3.0`
b)
Theoretical `F_(i n)`
`IMA = F_(out)/F_(i n)`
`F_(i n)= F_(out)/IMA`
`F_(i n)= (900\ N)/3.0`
`F_(i n)= 300\ N`
c)
`AMA = F_(out)/F_(i n) ` where `F_(i n)` is the actual `F_(i n)`
`AMA = (900\ N)/(400\ N) `
`AMA = 2.25`
d)
Efficiency`= (AMA)/(IMA) = (2.25)/(3.0)`
Efficiency`=0.75` |