Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } div.speak{display:none;} i.speak{float: right;margin-top:-10px;cursor:pointer;} 3. A block weight 900\ N was pulled up on an inclined plane with a force of 400\ N shown below. Assume the inclined plane is frictionless. a) What is IMA of this machine? b) Calculate the theoretical F_(i n). c) What is AMA of this machine? d) What is Mechanical efficiency of this machine?3. A block weight 900\ N was pulled up on an inclined plane with a force of 400\ N shown below. Assume the inclined plane is frictionless. a) What is IMA of this machine? b) Calculate the theoretical F_(i n). c) What is AMA of this machine? d) What is Mechanical efficiency of this machine? Hint IMA = F_(out)/F_(i n)=L/H Efficiency= (AMA)/(IMA) Answer a) IMA =3.0 b) F_(i n)= 300\ N c) AMA = 2.25 d) Efficiency=0.75 Show Steps Given: F_(out) = 900\ N Actual F_(i n) = 400\ N L = 9.0\ m H = 3.0\ m Equations: IMA = F_(out)/F_(i n)=L/H Efficiency= (AMA)/(IMA) Solution: a) IMA =L/H = (9.0\ m)/(3.0\ m) IMA =3.0 b) Theoretical F_(i n) IMA = F_(out)/F_(i n) F_(i n)= F_(out)/IMA F_(i n)= (900\ N)/3.0 F_(i n)= 300\ N c) AMA = F_(out)/F_(i n)  where F_(i n) is the actual F_(i n) AMA = (900\ N)/(400\ N)  AMA = 2.25 d) Efficiency= (AMA)/(IMA) = (2.25)/(3.0) Efficiency=0.75