Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } div.speak{display:none;} i.speak{float: right;margin-top:-10px;cursor:pointer;} 4. A 30-cm-long and 5.0-cm-width wedge cut in a block with a force of 40\ N and produce 200\ N output force as shown. Find a) Ideal mechanical advantage (IMA)? b) The theoretical output Force? d) Actual mechanical advantage (AMA)? e) Efficiency?4. A 30-cm-long and 5.0-cm-width wedge cut in a block with a force of 40\ N and produce 200\ N output force as shown. Find a) Ideal mechanical advantage (IMA)? b) The theoretical output Force? d) Actual mechanical advantage (AMA)? e) Efficiency? Hint IMA = F_(out)/F_(i n)=L/W Efficiency= (AMA)/(IMA) Answer a) IMA =6.0 b) F_(out)= 240\ N c) AMA = 5.0 d) Efficiency=0.83 Show Steps Given: Actual F_(out) = 200\ N F_(i n) = 40\ N L = 30\ m W= 5.0\ m Equations: IMA = F_(out)/F_(i n)=L/W Efficiency= (AMA)/(IMA) Solution: a) IMA =L/w = (30\ m)/(5.0\ m) IMA =6.0 b) Theoretical F_(out) IMA = F_(out)/F_(i n) F_(out)= F_(i n)timesIMA F_(out)= (40\ N)times6.0 F_(out)= 240\ N c) AMA = F_(out)/F_(i n)  where F_(i n) is the actual F_(i n) AMA = (200\ N)/(40\ N)  AMA = 5.0 d) Efficiency= (AMA)/(IMA) = (5.0)/(6.0) Efficiency=0.83