Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } div.speak{display:none;} i.speak{float: right;margin-top:-10px;cursor:pointer;} 5. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack. The car raised 2.0 cm with every full turn of the handle. What is the ideal mechanical advantage of the jack?5. A jackscrew with a handle 30.0 cm long is used to lift a car sitting on the jack. The car raised 2.0 cm with every full turn of the handle. What is the ideal mechanical advantage of the jack? Hint IMA = (2πR)/P Answer IMA = 94 Show Steps Given: R = 30.0\ cm P = 2.0\ cm Equation: IMA = (2πR)/P Solution: IMA = (2π(30.0\ cm))/(2.0\ cm) IMA = 94