Menu div.question,div.steps {font-size: 16px; padding: 10px;line-height: 20px; margin: 20px;} div.question{border: 1px solid #ccc;} div#solution .button{font-size: 20px; margin: 20px; width: 200px; padding: 10px; text-align: center;} div.hint,div.answer,div.steps{display: none;} div.pre_next{font-size: 30px; width:90%; margin:auto;} div.pre_next a.nav_pre{float:left;} div.pre_next a.nav_next{float:right;} div.title div.notes{ font-family:sans-serif, Arial; font-size: 18px; } div.speak{display:none;} i.speak{float: right;margin-top:-10px;cursor:pointer;} 6. The following pulley system made of 3 massless pulleys, and the load weight W = 300\ N. a) What is the IMA of this system? b) Find magnitude of tension T1,T2, T3, T4, T5 and T6.6. The following pulley system made of 3 massless pulleys, and the load weight W = 300\ N. a) What is the IMA of this system? b) Find magnitude of tension T1,T2, T3, T4, T5 and T6. Hint IMA is equal to the number of rope segments on the moving pulleys. Answer (a)IMA = 3 (b) T_1=T_2 = T_3= T_4 = 100\ N T_5 = 200\ N T_6 = 200\ N Show Steps (a) IMA is equal to the number of rope segments pulling up on the moving pulleys (or Loading object). Count segments we get: IMA = 3 (b) Given: W = 300\ N IMA = F_(out)/F_(i n) = W/T_1 T_1 = W/(IMA) T_1 = (300\ N)/3 T_1 = 100\ N since T_1, T_2 , T_3, T_4 are one rope. T_1=T_2 = T_3= T_4 = 100\ N T_5 = T_1+T_2 T_5 = 200\ N T_6 = T_3+T_4 T_6 = 200\ N