1. Three charged particles are arranged in a line, as shown below. Calculate the net electrostatic force on particle `Q_2` due to the other two charges.
1. Three charged particles are arranged in a line, as shown below. Calculate the net electrostatic force on particle Q_2 due to the other two charges.
Hint
`F = k(Q_1Q_2)/r^2`
Answer
`sum F= 0.5\ N` toward `Q_1`
Show Steps
Given: `Q_1 = -8.0\ µC = -8.0 times 10^-6\ C` `Q_2 = +3.0\ µC = +3.0 times 10^-6\ C` `Q_3 = -4.0\ µC = -4.0 times 10^-6\ C` Equation: `F = k(Q_1Q_2)/r^2` known: `k = 9.0 times 10^9\ N•m^2//C^2` Solution: Let `F_(12)` be the positive direction `sum vec(F) = vec(F)_(12) + vec(F)_(32) = F_(12) - F_(32)` `F_(12) = k(Q_1Q_2)/(r_(12))^2` `F_(12) = (k = 9.0 times 10^9\ N•m^2//C^2)((8.0times10^-6\ C)(4.0 times 10^-6\ C))/((0.3\ m))^2` `F_(12) = 3.2\ N` `F_(32) = k(Q_2Q_3)/(r_(23))^2` `F_(32) = (k = 9.0 times 10^9\ N•m^2//C^2)((3.0times10^-6\ C)(4.0 times 10^-6\ C))/((0.2\ m))^2` `F_(23) = 2.7\ N` `sum F= F_(13) - F_(23)` `sum F= (3.2\ N) - (2.7\ N)`
`sum F= 0.5\ N` toward `Q_1`