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2. A uniform electric field has the magnitude of `12\ V//m`. Point `A` and `B` are inside the electric field as shown. Point `A` is `10\ cm` away from ground and point `B` is `50\ cm` form the ground. Find the electric potential at point `A` and `B`.
2. A uniform electric field has the magnitude of 12\ V//m. Point A and B are inside the electric field as shown. Point A is 10\ cm away from ground and point B is 50\ cm form the ground. Find the electric potential at point A and B.  Given:
`E = 12\ V//m`
`d_A = 10\ cm = 0.10\ m`
`d_B = 50\ cm = 0.50\ m`
Equation:
`E = (∆V)/d`
Solution:
`E = (∆V)/d => ∆V = Ed`
a)
`∆V = V_A - 0 = Ed_A`
`V_A = (12\ V//m)(0.10\ m)`
`V_A = 1.2 V`
a)
`∆V = V_B - 0 = Ed_B`
`V_B = (12\ V//m)(0.50\ m)`
`V_B = 6.0 V` |