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5. If `61.5\ L` of oxygen at `18.0°C` and an absolute pressure of `2.45\ atm` are compressed to `48.8\ L` and at the same time the temperature is raised to `50.0°C`, what will the new pressure be?
5. If 61.5\ L of oxygen at 18.0°C and an absolute pressure of 2.45\ atm are compressed to 48.8\ L and at the same time the temperature is raised to 50.0°C, what will the new pressure be? `PV = nRT`
`P_2 = 3.43\ atm`
Given:
`V_1 = 61.5\ L`
`T_1 = 273 + 18 = 291\ K`
`P_1 = 2.45\ atm`
`V_2 = 48.8\ L`
`T_2 = 273 + 50 = 323\ K`
Equation:
`PV = nRT`
Solution:
Since amount of gas not change
`(PV)/T = nR =` constant
`=>`
`(P_1V_1)/T_1 = (P_2V_2)/T_2`
`P_2 = P_1(V_1T_2)/(V_2T_1)`
`P_2 = (2.45\ atm)((61.5\ L)(323\ K))/((48.8\ L)(291\ K))`
`P_2 = 3.43\ atm` |