|
6. A helium-filled balloon escapes a child's hand jat sea level and `20.0°C`. When it reaches an altitude of `3000\ m`, where the temperature is `5.0°C` and the pressure is only `0.70\ atm`, how will its volume compare to that at sea level?
6. A helium-filled balloon escapes a child's hand jat sea level and 20.0°C. When it reaches an altitude of 3000\ m, where the temperature is 5.0°C and the pressure is only 0.70\ atm, how will its volume compare to that at sea level? `PV = nRT`
`V_2/V_1 = 1.4`
`T_1 = 273 + 20 = 293\ K`
`P_1 = 1.00\ atm`
`T_2 = 273+5 = 278\ K`
`P_2 = 0.70\ atm`
Equation
`PV = nRT`
Solution:
Since amount of gas not change
`(PV)/T = nR =` constant
`=>`
`(P_1V_1)/T_1 = (P_2V_2)/T_2`
`V_2/V_1 = (P_1T_2)/(P_2T_1)`
`V_2/V_1 = ((1.00\ atm)(278\ K))/(( 0.70\ atm)(293\ K))`
`V_2/V_1 = 1.4` |