Given two equations: (1) `x + 5y = 12` (2) ` 3x + 2y = -3` 1st Step: Solve equation (1) `x=12-5y` 2nd Step: substitute `x` into equation (2) and solve `y` `3(12-5y)+2y = -3` `36-15y+2y = -3` `(-13)y = -3-36` `y = (-39)/(-13) ` `y = 3` 3rd Step: substitute `x` into 1st step equation `x = 12-(5times3)` `x = -3`