Displacement under constant Acceleration
`a = 0.5\ m//s^2`
area of triangle:
`S = 1/2 times base times hight`
`=>`
`∆x = 1/2 times t times at`
`=>`
area of triangle:
`S = 1/2 times base times hight`
`=>`
`∆x = 1/2 times t times at`
`=>`
`∆x = 1/2 at^2`
If initial velocity (`v_i`) not equals 0
`∆x = v_it +1/2 at^2`
Since `∆x = x_f - x_i` (final position - initial position)
`=>`
`x_f - x_i = v_it +1/2 at^2`
`=>`
`x_f = x_i + v_it +1/2 at^2`