The `70`-`L` steel gas tank of a car is filled to the top with gasoline at `20°C`. The car sits in the sun and the tank reaches a temperature of `40°C`. How much gasoline do you expect to overflow from the tank? Given: `V_0 = 70\ L` `T_0 = 20°C` `T = 40°C` Known: `beta_g = 950 times 10^(-6)\ C°^(-1)` `beta_s = 36 times 10^(-6)\ C°^(-1)` Equation: `∆V = betaV_0∆T` Solution: Both the gasoline and the tank expand as the temperature increases. The volume of overflowing gasoline equals the volume increase of the gasoline minus the increase in volume of the tank. Gasoline: `∆V = beta_gV_0∆T = (950 times 10^(-6)\ C°^(-1))(70\ L)(40°C - 20°C) = 1.3 L` Tank: `∆V = beta_sV_0∆T = (36 times 10^(-6)\ C°^(-1))(70\ L)(40°C - 20°C) = 0.050 L`