Given `angleA=50°` and hypotenuse(`r`) `=2` as show below, what are the length of the opposite(`y`) and adjacent(`x`) side of `angleA`? Solution: `Sin angleA = y/r` so, `sin50° = y/2` `=> y = 2sin50°` `= 2 times 0.766` `=1.532` `cos angleA = x/r` so, `cos50° = x/2` `=> x = 2cos50°` `= 2 times 0.643` `=1.286`